You can configure other options as mentioned in the above table. In the above example, first parameter is a request url which will return JSON data. In the options parameter, we have specified dataType and timeout options. The timeout parameter specifies request timeout in milliseconds. We have also specified callback functions for error and success. The ajax method can send all type of http requests.
The following example sends http POST request to the server. In the above example, first parameter is a url which is used to submit the data. Also, we have specified data option as a JSON object containing data which will be submitted to the server. For a more realistic example, see step 3 of this article. After making a request, you will receive a response back. At this stage, you need to tell the XMLHttp request object which JavaScript function will handle the response, by setting the onreadystatechange property of the object and naming it after the function to call when the request changes state, like this:.
Note that there are no parentheses or parameters after the function name, because you're assigning a reference to the function, rather than actually calling it. Alternatively, instead of giving a function name, you can use the JavaScript technique of defining functions on the fly called "anonymous functions" to define the actions that will process the response, like this:.
Next, after declaring what happens when you receive the response, you need to actually make the request, by calling the open and send methods of the HTTP request object, like this:.
The parameter to the send method can be any data you want to send to the server if POST -ing the request. Form data should be sent in a format that the server can parse, like a query string:. For example, use the following before calling send for form data sent as a query string:.
When you sent the request, you provided the name of a JavaScript function to handle the response:. What should this function do? First, the function needs to check the request's state.
Aliaksandr Sushkevich 8, 6 6 gold badges 33 33 silver badges 39 39 bronze badges. Alex Alex This should be marked as a correct answer because it's simple, efficient and works great. For example, with. Is it possible to bunch the requests ajax Be careful with the fail case. Unlike done , fail fires immediately on the first fail and disregards the remaining deferreds. As I pointed out in a comment to the OP's question: he might want to indicate more precisely what he meant by "done". It is great to give people exposure to the when method, and to promises in general, but I think this isn't the best answer.
If any of those ajax functions anywhere down the line create another ajax request, and then don't integrate that new promise into the chain correctly For example, I can't use this technique without modifying the Shopify library I'm using for ajax add-to-cart behaviour, because it wasn't written in a 'promisy' way, and never returns the xhr objects it creates.
Does this make sense? Still a great answer, though! Show 13 more comments. Arsen Khachaturyan Arsen Khachaturyan 6, 4 4 gold badges 35 35 silver badges 37 37 bronze badges. It's not very good if you don't want to wait for all AJAX calls to return.
The question is specific about waiting for the AJAX calls you've made on your own called inside another function, as the OP wrote. Some other code may have made another AJAX call that you don't want to wait for. Compared to the when solution, it has the advantage to work even if the number of ajax calls is not known. Compared to the when solution, it has the large disadvantage not to work well together with other components, since it shares a document-wide global state.
If there is some long polling going on continuously, it might even never fire. You're not correct AdrienBe, ajaxStop handles all ajax requests no matter do they succeed or not, just as proof of my words look at this jsfiddle. Show 7 more comments. Community Bot 1 1 1 silver badge.
It looks like you've forgotten to give proper attribution to this answer , I've added it. Use the ajaxStop event. Igor Ivancha 3, 4 4 gold badges 29 29 silver badges 39 39 bronze badges. This assumes that you know there won't be any other AJAX requests on the page, not a very good assumption — Juan Mendes. As of jQuery 1.
Correct me if I'm wrong but won't this turn your project into an "old school web forms" site? I mean if you your entire page has to wait for a request before it can continue then what's the point of the ajax request in the first place?
BillRuhl in our case, I'm looping through a jquery collection to build new stuff and need to know about the whole collection when it's done, before making some layout adjustments. Doesn't seem like a particularly unusual case. Would be bad if a bunch of other ajax stuff might be in process, but it won't be, here.
BBonifield BBonifield 4, 16 16 silver badges 36 36 bronze badges. This seems like it would overly complicate a trivial problem.
It's really not all that complicated. Counting semaphores are a common mechanism in CS. If you prefer though, the example using jQuery queues would work as well without having to implement the semaphore yourself. To learn more about how Varnish Cache can be used to speed up your website please download our guide.
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