How can you prove a rhombus




















From the picture, it looks kind of like a parallelogram. You have to be careful, though, because looks can be deceiving. It also looks like the diagonals of the newly created quadrilateral are perpendicular. If the drawing is accurate, you might be tempted to conclude that the quadrilateral is a rhombus. Let's prove it. You need a serious game plan for this one. Because you're dealing with a rectangle, you know that m?

So by the SAS Postulate,? So opposite sides are congruent and quadrilateral MNOP is a parallelogram. Also, adjacent sides are congruent, so parallelogram MNOP is a rhombus.

Explanations 1. Siddharth Namachivayam. When proving a quadrilateral is a rhombus, we must know several things: 1 A rhombus is a parallelogram with equal side lengths. Since all sides of this quadrilateral are equal then quadrilateral ABCD must be a rhombus. While one method of proof will be shown, other methods are also possible. Did you know Proof 1. Proof 2. A quadrilateral whose diagonals bisect each other is a parallelogram, so this test is often stated as.

This figure is a rhombus because its diagonals bisect each other at right angles. If the circles in the constructions above have radius 4cm and 6cm, what will the side length and the vertex angles of the resulting rhombus be? If each diagonal of a quadrilateral bisects the vertex angles through which it passes, then the quadrilateral is a rhombus. Let ABCD be a quadrilateral, and suppose the diagonals bisect the angles, then let.

The converse of a property is not necessarily a test. The following exercise gives an interesting characterisation of quadrilaterals with perpendicular diagonals. One half is straightforward, the other requires proof by contradiction and an ingenious construction. We usually think of a square as a quadrilateral with all sides equal and all angles right angles.

Now that we have dealt with the rectangle and the rhombus, we can define a square concisely as:. A square thus has all the properties of a rectangle, and all the properties of a rhombus. The intersection of the two diagonals is the circumcentre of the circumcircle through all four vertices.

We have already seen, in the discussion of the symmetries of a rectangle, that all four axes of symmetry meet at the circumcentre.

A square ABCD is congruent to itself in three other orientations,. The centre of the rotation symmetry is the circumcentre, because the vertices are equidistant from it.

The most obvious way to construct a square of side length 6cm is to construct a right angle, cut off lengths of 6cm on both arms with a single arc, and then complete the parallelogram. Alternatively, we can combine the previous diagonal constructions of the rectangle of the rhombus.

Construct two perpendicular lines intersecting at O , draw a circle with centre O , and join up the four points where the circle cuts the lines. What radius should the circle have for the second construction above to produce a square of side length 6cm? Some of the distinctive properties of the diagonals of a rhombus hold also in a kite, which is a more general figure.

Because of this, several important constructions are better understood in terms of kites than in terms of rhombuses. A kite is a quadrilateral with two pairs of adjacent equal sides. A kite may be convex or non-convex, as shown in the diagrams above. The definition allows a straightforward construction using compasses.

The last two circles meet at two points P and P 0 , one inside the large circle and one outside, giving a convex kite and a non-convex kite meeting the specifications. Notice that the reflex angle of a non-convex kite is formed between the two shorter sides. What will the vertex angles and the lengths of the diagonals be in the kites constructed above?

The congruence follows from the definition, and the other parts follow from the congruence. Using the theorem about the axis of symmetry of an isosceles triangle, the bisector AM of the apex angle of the isosceles triangle ABD is also the perpendicular bisector of its base BD. The converses of some these properties of a kite are tests for a quadrilateral to be a kite. If one diagonal of a quadrilateral bisects the two vertex angles through which it passes, then the quadrilateral is a kite.

If one diagonal of a quadrilateral is the perpendicular bisector of the other diagonal, then the quadrilateral is a kite. Is it true that if a quadrilateral has a pair of opposite angles equal and a pair of adjacent sides equal, then it is a kite?

Three of the most common ruler-and-compasses constructions can be explained in terms of kites. Notice that the radii of the arcs meeting at P need not be the same as the radius of the first arc with centre O. Notice that the radii of the arcs meeting at Q need not be the same as the radii of the original arc with centre P.

In the diagram to the left, the radii of the arcs meeting at P are not the same as the radii of the arcs meeting at Q. Trapezia also have a characteristic property involving the diagonals, but the property concerns areas, not lengths or angles. A trapezium is a quadrilateral with one pair of opposite sides parallel. Using co-interior angles, we can see that a trapezium has two pairs of adjacent supplementary angles. Conversely, if a quadrilateral is known to have one pair of adjacent supplementary angles, then it is a trapezium.

The diagonals of a convex quadrilateral dissect the quadrilateral into four triangular regions, as shown in the diagrams below.



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